I’m sorry, that’s too many going up my anus.

silly goose, it’s not like they’re actually going to guillotine him as trump rioters tried to hang mike pence.

zipties, cloth, and nap time!

well, generally these can range from a few hundred dollars to several thousand or 10s of thousands of dollars. The ones we use in my university are about the 10s of thousands range.

That said, you can find some for 100,000 to 200,000

signal generator - $2000

oscilioscope - $200000

nope, and that confirms it.

this was me buying $100 yoyos… then I got an associates in applied mathematics and I now can’t stop talking about it.

moral of the story: every hobby leads to math autism

I mean were talking about skin and tissue it will bend and stretch when it comes in contact to pressure. Also energy depends on mass not just velocity/speed. It would need to have a large enough energy while being precise enough to not be distributed over a surface to penetrate and damage tissue.

do you know why bullets penetrate tissue, its because it has a large enough kinetic energy fixated on a very small region of area. Similarly light that is emitted by a radioactive source penetrate and damage skin cells from the same principles.

don’t forgot signal processing. Complex number theory is used a lot when it comes down to Fourier transforms of discrete or continuous functions.

but yea the naming convention of “imaginary numbers” is pretty bad, we did the same thing for negative numbers (we called it imaginary) when people couldn’t comprehend of a negative quantity.

negative numbers are defined from a conservative system, basically a gain/loss relationship: if I have 2 apples and I give away 1 to a friend, I have 1 apple left, that loss – that apple I gave to a friend – is the negative quantity. For imaginary numbers, we don’t really have a way to comprehend an imaginary quantity; what does it mean that I have sqrt(-1) apples.

for some reason mine just shows diagonal elements 1/0 when I do inv(myself) * myself.

keeps the doctor away!

thanks, I’m going to set it as a banner on my linkedin.

insert image of “your Linux installation is fucked”

does he have the video’s research published?

there is no such thing as a gas powered computer. Maybe they meant a gas powered plant that would transmit electricity.

there is no gas powered computer, that’s the equivalent of saying I can make weed out of plutonium.

I can’t even look at the page because these corporate shills have to track me one way or another, it’s probably just coorporate propaganda.

I guess you didn’t read my last part, humans are deterministic by nature; they draw trends based on patterns. if you wanted to win with one ship just place that ship in a place that is completely counterintuitive to what they expect. Having one ship does have strategic implications, that it narrows the possibility of being hit. Combine that with counterintuitive placement of said ship and your opponent is as good a player as a fish.

so does probability play a role in battleship? yes, it removes the statistical likeliness of being hit (ignoring the premise of humans drawing generalizations by pattern recognition). It is drastically less likely to hit one ship than 5, all you need to do is place that one ship in a position that is counterintuitive to the trend to remove any biases of your opponent who has played several games already.

what are you going on about, that probability depends on the number of turns you get? last I checked it, no it does not depend on that.

the argument I’m trying to make is it’s statistically less likely to hit that 5 point battleship (probability is 5%) compared to the 17 points in ships spread abitrarily (probability is 17℅). IT DOES NOT DEPEND ON THE NUMBER OF TURNS IT TAKES TO SINK ALL 5 BATTLESHIP’S. The probability does depend after the first event has occurred (where you’ve hit one of those pieces). Whether you get a hit on your first turn or the first hit in 30 turns, it does not matter. probability does not depend on the number of turns it takes.

technically speaking the probability calculated at the beginning is when the number of trials (theoretically) approach to infinity. The 1/6 probability to role a six sided die on a number (for example, lets say 6) is after doing trial and error of rolling a 6. Now whether you get the 6 on the first try or the 100th try these are approximations of the 1/6 th probability. As you do more and more trials it does eventually converge to the 1/6 th probability.

So yes, technically speaking someone could hit the standalone stacked battleship in one try, probability and statistics doesn’t concern that. So if that concerns you, psychologically manipulate your openent by putting your battleship in the first row.

I’ll add to this, it’s not just about finding the initial probability since the probability for event B given A, or event C given A and B, these would increase the liklihood of being found. I couldn’t tell you exactly what the probability is but say for example event B given A, it would be 1/n for n being the number of legal spaces around A. So if the ship was in the middle of the board it would have the smallest probability of being found but if you’re along a wall, there’s only 3 possible legal spaces so the probability increases to 33.3℅, and if A was sandwitched between two walls, the probability of B is 50℅.

so if there’s a moral to this story, assert dominance and put all your pieces in the center.

hold on there, it actually does have strategic advantage from a statistical perspective.

the basic notion is that for a probability of event A to occur it is proportional to the area of the event; so if larger area, larger probability, smaller area, smaller probability.

if we take that idea and apply the same basis to battleship you could say the probability as the sum of each probability of each point which is 0℅ if we span the area to infinity.

practically speaking, this is not true as you can’t span to an infinite scale, but you could say that the probability of hitting a point is 1℅ since battleship is a 10 x 10 grid so the probability is just 1/(10 * 10) = 0.01. Then the probability gets more complicated since you are being asked what is the probability of the second, third, fourth, etc… point being hit given that initial probability. the probability grows dependent on the first point being hit.

I’m sure there is a way to find algorithmically an optimal method to finding in what location are the best positions in battleship, but generally speaking, no, there are worse conditions that have a higher probability of being guessed

here’s another one if you use chatGPT to solve the first one. Anyone who is fully optimized should be able to solve analytically shrodingers second order partial differential equation.

start with those problems, then we’ll talk if you are fully optimized.

find all possible eigenvalues and eigenvectors for the following 3 x 3 square matrix [1/0 1/0 1/0; 1/0 1/0 1/0; 1/0 1/0 1/0]