This program prompts the user to input a phrase, then counts the number of vowels and consonants present in that phrase, ignoring uppercase letters and considering only alphabetical characters. ```py def count_vowels_consonants(phrase): vowels = 0 consonants = 0 # Converting the phrase to lowercase for easier comparison phrase = phrase.lower() # Defining a list of vowels vowels_list = ['a', 'e', 'i', 'o', 'u'] # Iterating over each character in the phrase for character in phrase: # Checking if the character is a letter if character.isalpha(): # Checking if the character is a vowel if character in vowels_list: vowels += 1 else: consonants += 1 return vowels, consonants # Asking the user to input a phrase user_phrase = input("Enter a phrase: ") # Calling the function and storing the result num_vowels, num_consonants = count_vowels_consonants(user_phrase) # Displaying the results print("Number of vowels:", num_vowels) print("Number of consonants:", num_consonants) ``` I leave you with another challenge, which you can answer in the comments. **Challenge**  * `Hangman`: Implement the classic game of hangman, where the player must guess a hidden word before exhausting all attempts.👇